Question 850315
You listed a point and an equation.  Do you want something from both of them?  


Solving for y:
Your first three steps are understood.  What you are trying to do after that is unknown.  If you want to subtract negative two from the left member, then you must do so to the right member also.  Finally, your last step is the wrong equation.


A guess is that you are attempting to put into point-slope form, but that seems badly reasoned.


Using the given point in the original equation,
{{{7*(9)-5(-2)=9}}}
{{{63+10=9}}}
{{{73=9}}} IS FALSE._________{{{cross(73=9)}}}.
This means that the given line does not contain the given point.


Back to just solving your original equation for y:
7X-5y=9   (Let us use lower case only)
{{{7x-5y=9}}}
{{{-5y=-7x+9}}}
{{{y=(7/5)x+9/(-5)}}}
{{{highlight(y=(7/5)x-9/5)}}}  or  equivalently {{{y=(7/5)x-1&4/5}}}.
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Now having the equation in general form (slope-intercept form), what do you want to do with the given point?