Question 850156
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Hi,
P(at least one woman) = 1 - P(no women) = 1 - {{{(10C3)(8C0)/(18C3)}}}
For ex: Notation used for Combinations:
nCx = *[tex \large{{n}\choose{x}}] = {{{(n!)/x!(n - x)!)}}} 
10C3 = *[tex \large{{10}\choose{3}}] = {{{(10!)/(3!7!))}}} 

{{{(10C3)(8C0)/(18C3)}}} = {{{((10*9*8)/(3*2*1))/ ((18*17*16)/(3*2*1))= (10*9*8)/(18*17*16)}}}
More SimplY: Using 'counting'...(1st 10 men, 18people, then 9 men, 17people ...
P(at least one woman) = 1 - P(no women) = 1 - {{{(10/18)(9/17)(8/16)}}}