Question 850071
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
p = .05,  n = 100
using TI Calculator
P(x=3) = The syntax is binompdf(n, p, x-value)= binompdf(100, .05,3)
Or
 P = *[tex \large{{100}\choose{3}}](.05)^3(.95)^100  
Note: The probability of x successes in n trials is: 
P (x)= *[tex \large{{n}\choose{x}}] (p)^x(q)^(n-x) where p and q are the probabilities of success and failure respectively. 
In this case p = .05 & q  = .95
*[tex \large{{n}\choose{x}}] = {{{(n!)/x!(n - x)!)}}} 
*[tex \large{{100}\choose{3}}] = {{{100*99*98/(3*2) = 161700}}}
B. What is the probability, rounded to four decimal places that the box will contain at most 7 defective bolts? 
find P(x &#8804; 7)= binomcdf(n, p, largest x-value) = binomcdf(100, .05, 7).
 c. what is the probability, rounded to four decimal places that the box will contain less than 4 defective bolts?
find P(x < 4)= binomcdf(n, p, largest x-value) = binomcdf(100, .05, 3).