Question 850057
Two consecutive positive integers, n and n+1.
{{{n(n+1)=306}}}
{{{n^2+n-306=0}}}, and needs to be factorable.


306=102*3=34*3*3=2*17*3*3=17*18


{{{n^2+n+306=(n-17)(n+18)=0}}}
{{{n=17}}}.

That means {{{n+1=18}}}.


The two consecutive whole numbers are 17 and 18.