Question 849960
Water initially at 190°F. is left in a room of temperature 70°F to cool. After t minutes, the temperature T of the water is given by T(t) = 70 + 120e – 0.096 t  
Find the temperature of the water 10 minutes after it is left to cool.  (Round to the nearest degree.)
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I think it's {{{T(t) = 70 + 120*e^(-0.096t)}}} ?  
T(10) = 116 degs