<PRE><B>Question 849949</B>
If you know that 25 women and 22 men are available for invitation but only 12 will attend, what is the probability that you would have six men and six women attend?
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# of ways to succeed/# of groups of 12 = 
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25C6*22C6/47C12 = 0.2529
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The probability that six men and six women attend is 0.2529
Cheers,
Stan H.
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