Question 849840
 α and β are quadrant I angles with 
cos(α) = 15/17 
Therefore sin(alpha) = sqrt[17^2-15^2]/17 = 8/17
Then tan(alpha) = 8/15
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and csc(β) = 41/9
sin(Beta) = 9/41
So, cos(Beta) = sqrt[41^2-9^2]/41 = 40/41
Then tan(Beta) = 9/41
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Find tan(α - β) = [tan(a)-tan(b)]/[1+tan(a)tan(b) 
Note: Just plug in the numbers.
Cheers,
Stan H.
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