Question 849726
Find the distance between the two parallel lines given by the equation: 5x-4y=22 and -75x=150-60y
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5x-4y=22 --> y = (5/4)x - 11/2
-75x=150-60y --> y = (5/4)x + 5/2
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y = (5/4)x - 11/2
(0,-11/2) is a point
Perpendicular thru the point --> y = (-4/5)x - 11/2
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y = (-4/5)x - 11/2 = (5/4)x + 5/2
-16x - 110 = 25x + 50
x = -160/41
y = 640/205 - 11/2 = 256/82 - 451/82 = -195/82
Intersection at (-160/41,-195/82)
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{{{d^2 = diffy^2 + diffx^2}}}

d =~ 4.95