Question 9225
This problem is a trigonometry problem using triangles:

It involves the use of Pythagorean Theorem, which says: "In algebraic 
terms, {{{a^2+b^2=c^2}}} where c is the hypotenuse while a and b are the 
sides of the triangle.

Think of the basball diamond as a square, and at each base a corner of 
the square with each corner being a 90 degree angle.  So if we draw a 
line from third base to first base we cut the square in half.

We now have two right triangles.

The first leg of the triangle is from first base to second base, the 
second leg of the triangle is from second base to third base and the 
distance from third base across the field to first base is the hypotenuse.

we can now solve this problem.

Distance from First to Second = 90 Ft., we will call this A

Distance from Second to Third = 90 Ft., We will call this B

Throwing distance from third to First = ?, We will call this C

So we know that {{{A^2+B^2=C^2}}}

So we subsitute the numbers we know:

{{{90^2+90^2=C^2}}}

So squaring the numbers we get: {{{8100+8100=C^2}}}

We then take the square root of both sides to get

{{{sqrt(8100+8100)=C)}}}
{{{sqrt(16200)=C}}}

127.28 = C

So the answer to the nearest Ft. is 127 Feet.  Is how far the 3rd. Baseman threw the ball to the fist baseman