Question 849597
{{{(a+bi)+(c+di)=10i}}} would indicate that {{{a=-c}}}.


The variablized complex numbers may then be called a+bi and -a+di.


{{{(a+bi)-(-a+di)=-4}}}
{{{a+a+bi-di=-4}}}
{{{2a+(b-d)i=-4+0*i}}}
{{{2a=-4}}} and {{{b-d=0}}}
{{{highlight(a=-2)}}}


EQUATIONS

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b+d=10
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b-d=0
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Adding these for Elimination, 2b=10, so {{{highlight(b=5)}}} and {{{highlight(d=5)}}}


The two numbers are {{{a+bi=highlight(-2+5i)}}} and {{{-a+di=highlight(2+5i)}}}