Question 849611
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Hi,
quadratic formula
y = ax^2 + bx + c = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
 {{{x = sqrt(5)/3}}}  a root
{{{x = (0 +- sqrt( 0-4*a*c ))/(2*a) }}} 
      2a = 3,  -4(3/2)c = 5, -6c = 5, c = -5/6
  {{{y = (3/2)x^2 - 5/6}}}
  (3/2)= a.  It is the coefficient of x^2
    0 =  b
  -5/6 = c
y = ax^2 + bx + c 
  {{{y = (3/2)x^2 - 5/6}}}