Question 849543
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
1) 2log(2x+8)=4  {{{10^2 = 2x+8}}}
2) logx-log4= log(x/4) = -2   {{{1/10^2 = x/4}}}
3) e^ln5x=20  {{{5x = 20}}}
4) e^x+6 = -4  |Cannot take ln of both sides of EQ to solve;  NO Solution
5) ln(x-3)=2  {{{e^2 = x-3}}}
6) log base5 (3x+20)- 3log base5 2 = {{{log(5,(3x+20)/8)) }}} =2  {{{5^2 = (3x+20)/8))}}}

*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
*[tex \large\ \ ln e^x = x]****
{{{ e^(lnx) = x}}}
{{{log(a, p) = log(b,p)/ (log(b, a)) }}}