Question 71529
Let x=first integer
Then x+2=second integer
And x+4=third integer

3(x+2)=three times the second number
2(x+4)=twice the third number

Now we are told that: 
3(x+2)+2(x+4)=7x  get rid of parens

3x+6+2x+8=7x  collect like terms
5x+14=7x  subtract 5x from both sides
14=7x-5x
14=2x divide both sides by 2
x=7------------------first integer
x+2=9----------------------second integer
x+4=11--------------------------3rd integer

CK

3(9)+2(11)=7(7)
27+22=49
49=49


Hope this helps-----ptaylor