Question 849419
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Hi,
<img src='http://img585.imageshack.us/img585/479/rectangle.png' border='0'/></a>
Let x represent  the width
(x-1yd)x = 21yd^2
 x^2 -x -21 = 0   (Tossing out the negative solution for unit measure)
{{{x = (1 + sqrt( 85 ))/(2) }}}, the width
{{{x = (sqrt( 85 ))/(2) }}}, the length