Question 849275
If you had {{{ log( a ) = 0 }}}
you could rewrite it as
{{{ 10^0 = a }}} assuming {{{ 10 }}}
is the base
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So, you could rewrite your problem as:
{{{ 10^0 = 5 - 2x }}}
Anything to the zero power is one, so
{{{ 1 = 5 - 2x }}}
{{{ 2x = 5 - 1 }}}
{{{ 2x = 4 }}}
{{{ x = 2 }}}