<PRE><B>Question 849263</B>
Suppose the probability that the mechanic fixes your car right the first time
is 0.9. Find the odds against your car being repaired right on the first attempt.
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P(for) = 0.9
P(against) = 0.1
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Odds against = P(against)/P(for) = 0.1/0.9 = 1:9
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Cheers,
Stan H.
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