Question 849240
{{{3/((x-1)(x+5))}}}

Let's start with the domain. What would be the "acceptable" values of x? Really in a rational function, we just don't want to divide by 0. The values that make us 0 is x-1 = 0  and x+5 =0  so x=1 and x=-5. These are the unacceptable values so we'll represent our domain as {{{x <> -5}}}, {{{x <> 1}}}.

Now the range. What is the minimum value that y can take on? That's where we have the maximum value in the denominator. Since we're talking about a polynomial in that case, our function approaches infinity (or just some really large number). What happens when we divide by a really large number? We get pretty close to 0. 

Now what about the maximum value y can take on? Well, what's the minimum value that our denominator can take on? We can't quite get to 0, but we can get close. If we divide 3 by a very very small number, we'll get a very large number. In fact we'll approach infinity. 

So putting that together our range is (0,{{{infinity}}})