Question 849153
The standard form of the equation of a parabolas is y=2x^2+16x+17 what is the vertex form of the equation? 
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Vertex form of equation: y=A(x-h)^2+k, A=coefficient, (h,k)=(x,y) coordinates of the vertex.
A>0, parabola opens up
A<0, parabola opens down
complete the square:
y=2(x^2+8x+16)+17-32
y=2(x+4)^2-15
This is a parabola that opens up with vertex at (-4,-15)