Question 849154
Assuming 2 of these dice are rolled. Make a table like you see below


<img width = "300" src = "http://bestcase.files.wordpress.com/2011/01/dicediagram.jpg">

(Image Source: <a href="http://bestcase.wordpress.com/2011/01/08/an-empirical-approach-to-dice-probability/">http://bestcase.wordpress.com/2011/01/08/an-empirical-approach-to-dice-probability/</a>)


Note: each cell is found by adding the row and column header. For instance, the '8' in row 3, column 5 is found by adding 3 and 5. So 3+5 = 8. The other cells are found this way.



You can see that there are 4 copies of '5' and 2 copies of '11'. So there are 4+2 = 6 copies of what we want (which is either 5 or 11). 


This is out of 6*6 = 36 possible outcomes. 


So the answer as a fraction is {{{6/36 = 1/6}}}