Question 848887
Log (base 2) x+3=log (base 2) x-3 + log (base 6) 36 +3
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{{{log(2,(x+3)) = log(2,(x-3)) + log(6,36) + 3}}}
{{{log(3,36) = 2}}}
{{{log(2,(x+3)) = log(2,(x-3)) + 5}}}
{{{5 = log(2,32)}}}
{{{log(2,(x+3)) = log(2,(x-3)) + log(2,32)}}}
{{{log(2,(x+3)) = log(2,32*(x-3))}}}
x+3 = 32*(x-3) = 32x - 96
31x = 99
x = 99/31