Question 71483
Remember, "log of" simply means "exponent of".


1. 5log(base37)37^9=
log(base37) 37^(9*5)
=9*5 or 45
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2. 3log(base24)24^-2/3=
log(base 24) 24^(-2/3*3)
=log(base 24) 24^(-2) 
= -2
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3. (Log(base7)8)/(log(base7)1/8) =
= log(base7)8 /[log(base7)1 - log(base7)8]
=log(base7)8 / -log(base7)8
= -1
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4. 10^(log(base100)9)=
10^[(log9)/log100]
=10^[(log9)/2]
=[10^log9]^(1/2)
=9^(1/2)
=3
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Cheers,
Stan H.