Question 848484
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Hi,
Midpoint Pt(x,y):  ( {{{(x[1] + x[2])/2}}} , {{{(y[1] + y[2])/2  )}}} )
{{{(-6 + x[2])/2 = -1}}} &#8658; {{{x[2] = 4}}}
{{{(8 + y[2])/2= 1}}} &#8658; {{{y[2] = -6}}}
other endpoint is (4,-6)