Question 71451
Y-3X=4
Y=3X+4 HAS A SLOPE OF 3 SO THE PERPENDICULAR LINE HAS A SLOE OF THE NEGATIVE RECIPROCAL OF 3 WHICH IS -1/3. NOW USIE THE X,Y VALUES TO SOLVE Y=mX+b FOR THE Y INTERCEPT (b).
6=-1/3*0+b
6=b SO THE LINE WITH A SLOPE OF -1/3 PASSING THROUGH (0,6) IS
Y=-1/3X+6
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Y=2X-3 HAS A SLOPE OF 2 THUS THE PERPENDICULAR SLOPE IS -1/2
4=-1/2*-2+b
4+1=b
5=b SO THE LINE WITH A SLOPE OF -1/2 PASSING THROUGH (-2,4) IS
Y=-1/2X+5
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3Y-X=0
3Y=X
Y=X/3 HAS A SLOPE OF 1/3 THUS THE PERPENDICULAR SLOPE IS -3
2=-3*0+b
2=b SO THE LINE WITH A SLOPE OF -3 PASSING THROUGH (0,2) IS
Y=-3X+2