Question 848138
Let (5, -2) be a point on the terminal side of an angle (theta) in standard position. Find the exact value of Cosecant of theta.
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x = 5
y = -2
Therefore r = sqrt[5^2+4^2] = sqrt(29)
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csc(t) = y/r = -2/sqrt(29)
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Cheers,
Stan H.