<PRE><B>Question 848367</B>
First, remember that the sum of all the angles in a triangle must equal 180 degrees. 

Let x = the measure of the first angle

Let x/2 = the measure of the second angle

Let 3x/2 = the measure of the third angle. 

Therefore 


x + x/2 + 3x/2 = 180. Now solve for x. Once you find x, you will find the measure for all three angles.




x + x/2 + 3x/2 = 180 

= x+ 4x/2 = 180

Multiply each side of the equation by 2 to get rid of the 2 in the denominator.


2[x + 4x/2] = 2(180).


2x + 4x = 360

6x = 360


Divide each side by 6


x = 60. 


Therefore the first angle x, is 60 degrees. The second angle, x/2 = 60/2 = 30 degrees. The third angle 3x/2 = 3(60)/2 = 90. 

60 + 30 + 90 = 180 so everything is correct. 




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