Question 848380
103 mod 5 =  3  (103)

3 * 103 mod 5 = 4   (103^2)

4 * 103 mod 5 = 2   (103^3)

2 * 103 mod 5 = 1   (103^4)

1 * 103 mod 5 = 3

(103^4)^11 = 103^44 =  1 mod 5

103^44 * 103^1 mod 5 = 1 * 3 =  3<--- residue