Question 848368
x+y>90
x*y<1800
x > 90 -y
y*(90-y) < 1800

90y - y^2 < 1800

y^2 -90y +1800 > 0 

(y-30)(y-60) > 0

y<30  y>60

x>60  x<30


So we just need two numbers of which one is less than 30 and the other is greater than 60.

Let's try 29 and 62

29 + 62 = 91>90

29*61 = 1798 < 1800