Question 71429
Your answer is correct:
{{{(4y/(y^2+6y+5))+(2y/(y^2-1))}}} Factor the denominators.
{{{(4y/((y+1)(y+5)))+(2y/(y-1)(y+1))}}} The common denominator is: (y-1)(y+1)(y+5) Add the fractions.
{{{(4y(y-1)+2y(y+5))/((y-1)(y+1)(y+5))}}} Simplify the numerator.
{{{(4y^2-4y+2y^2+10y)/((y-1)(y+1)(y+5))=(6y^2+6y)/((y-1)(y+1)(y+5))}}}={{{6y(y+1)/((y-1)(y+1)(y+5)) = 6y/((y-1)(y+5))}}}