Question 848097
Find the.equation of the line that passes through the points -3, -14 and 1 , -2
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Standard form for equation of a line: y=mx+b, m=slope, b=y-intercept
Using given points:
slope=∆y/∆x=(-2-(-14))/(1-(-3))=(-2+14)/(1+3)=12/4=3
equation: y=3x+b
solve for b using one of given points, say, (1,-2)
-2=3*1+b
b=-5
final equation: y=3x-5