Question 848069
---unfinished---


Not shown here, drew x by x square adjoined to a w by 3w rectangle, and showed the rectangle longer than the square.  There is an unadjoined length on the rectangle of 3w-x.   I might later create and upload a picture of this on an image host site.


Total area, {{{x^2+w*3w=256}}}
{{{highlight_green(w^2+3w^2=256)}}}


Fencing is perimeter.
{{{2x+x+(3w-x+3w+2w)=80}}}
simplifies to {{{2x+8w=80}}}
and to {{{highlight_green(x+4w=40)}}}


Two equations and two unknowns, highlighted in green.  I have not yet tried to solve that as a system...