<PRE><B>Question 848076</B>
The area of a triangle is 95 square feet.If the height is 5 more than the base, find the length of the height and base of the triangle. 
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Let base = x
Then height = x+5
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Equation:
x(x+5) = 95
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x^2 + 5x - 95 = 0
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x = [-5 +- sqrt(25-4*-95)]/2
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x = [-5 +- sqrt(405)]/2
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x = [-5 +- 9sqrt(5)]/2
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Positive solution:
x = (-5+9sqrt(5))/2 = 7.56 
x+5 = 12.58
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Cheers,
Stan H.
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