Question 848027
Multiply eq. 2 by 2 and add to eq. 1,
{{{3x+2y+2x-2y=6+4}}}
{{{5x=10}}}
{{{x=2}}}
Then use either equation to solve for {{{y}}}
{{{2-y=2}}}
{{{y=0}}}
(2,0) one point.
{{{drawing(300,300,-5,5,-5,5,grid(1),
circle(2,0,0.4),graph(300,300,-5,5,-5,5,x-2,(6-3x)/2))}}}