Question 848002
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Hi,
{{{(1/e)^(-x)=(1/e^2)^(x+1)}}}
{{{(e^(-1))^(-x)=(e^(-2))^(x+1)}}}
{{{e^x =e^(-2x+-2)}}}
    x = -2x-2
   3x = -2
    x = -2/3