Question 847842
The slope of the line that passes through (0,-4) and (2,0) is,
{{{m=(0-(-4))/(2-0)=4/2=2}}}
A perpendicular line would have a slope of,
{{{m*2=-1}}}
{{{m=-1/2}}}
.
.
{{{y=-(1/2)x+b}}}
Use the point (-6,6) to solve for {{{b}}}
{{{6=-(1/2)(-6)+b}}}
{{{6=3+b}}}
{{{b=3}}}
.
.
{{{y=-(1/2)x+3}}}
.
.
{{{drawing(300,300,-10,10,-10,10,grid(1),
circle(-6,6,0.4),
circle(2,0,0.4),
circle(0,-4,0.4),
graph(300,300,-10,10,-10,10,-(1/2)x+3,2x-4))}}}