Question 847878
Let the consecutive positive integers be x, x+1, x+2
then, x*(x+2) - (x-1)-1=6(x+2)
{{{x^2+2x-x-1-1=6x+12}}}
{{{x^2-5x -14 = 0}}}
{{{(x-7)(x+2)=0}}}
{{{x = 7, x= -2}}}
x = -2 is eliminated as it is given that integers are positive 
When x = 7 the numbers are 7,8,9 and smallest number 7.