Question 847872
Let {{{ d }}} = the distance in miles that the
65 mi/hr car has to travel to catch the 60 mi/hr car
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{{{ d - 2 }}} is the distance in miles that the
60 mi/hr car has to travel until the other car
catches up
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Start a stopwatch when the 65 mi/hr car is 2 miles
behind the 60 mi/hr car
Let {{{ t }}} = the time on the stopwatch when 
the cars meet
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Equation for 65 mi/hr car:
(1) {{{ d = 65t }}}
Equation for 60 mi/hr car:
(2) {{{ d - 2 = 60t }}}
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Substitute (1) into (2)
(2) {{{ 65t - 2 = 60t }}}
(2) {{{ 5t = 2 }}}
(2) {{{ t = .4 }}} hrs
and
(1) {{{ d = 65t }}}
(1) {{{ d= 65*.4 }}}
(1) {{{ d = 26 }}}mi
and, also:
{{{ d - 2 = 24 }}}
The 65 mi/hr car travels 26 mi
The 60 mi/hr car travels 24 mi
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check:
(2) {{{ d - 2 = 60t }}}
(2) {{{ 24 = 60*.4 }}}
(2) {{{ 24 = 24 }}}
OK