Question 847703
how do I solve this equation: (1/16) raised to power x equals 2 ??? 
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{{{(1/16)^x = 2}}}
The "hard way"
x*log(1/16) = log(2)
x = log(2)/log(1/16)
x = -0.25 = -1/4
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If you spot that 1/16 = 2^-4, then
{{{(2^-4)^x = 2}}}
{{{2^(-4x) = 2^1}}}
-4x = 1
x = -1/4