Question 847600
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Hi,
2log4+3log2 = {{{log(10, (4^2)(2^3)) = log(10,128)}}}
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]   Applied
*[tex \large\ \ log_bx + log_by = log_b(xy) ]   Applied
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]