Question 847552
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Hi,
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p = .30 and q = .70   and n = 5 
{{{ nCx = (n!)/x!(n - x)!)}}} 
Using the 'formula' is the 0r
Using TI Calculator
a. binompdf(5,.30, 0) = .1681  0r P = (.30)^0(.70)^5
 binompdf(5,.30, 1) = .3602    0r P = 5(.30)^1(.70)^4
binompdf(5,.30, 2) =  .3087    0r P = 10(.30)^2(.70)^3
binompdf(5,.30,3) =   .1323   0r  P = 10(.30)^3(.70)^2
binompdf(5,.30, 4) =  .0284   0r P = 5(.30)^4(.70)^1
binompdf(5,.30, 5) =  .0024   0r P = (.30)^5(.70)^0
c. P(x&#8805; 2) = 1 - P(x=0)- P(x=1) =   1 - .1681 - .3602
0r  Using TI
1 – binomcdf(n, p, largest x-value) = 1 - binomcdf(5,.30, 1)