<PRE><B>Question 847475</B>
let x be the circumference of the smaller wheel and 3.5x is the circumference of larger wheel
let n be the number of revolutions for the larger wheel
63 = n3.5x
63 = (n+10)x
solve for x in second equation and substitute in first
x = 63/(n+10)
63 = n(3.5 * 63/(n+10) )
63 = n (220.5/(n+10))
cross multiply fractions
63n+630 = 220.5n
630 = 157.5n
n = 4
substitute for n in second equation
63 = (4+10)x
x = 63/14 = 4.5 meters
circumference of smaller wheel is 4.5 meters and
circumference of larger wheel is 4.5 * 3.5 = 15.75 meters
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