<PRE><B>Question 847484</B>
let  m be the age of the man  let d be the age of the daughter

(m-10) = 6*(d-10)

m+10 = 2*(d+10)


m-10 = 6d - 60
m+10 = 2d + 20

m = 6d -50 (solving first one for m)


6d-50 + 10 = 2d + 20

6d -40 = 2d + 20

4d = 60

d = 15

m = 6(15) - 50 = 40

The man is 40, his daughter is 15.</PRE>