Question 847473
This is the binomial distribution and basically all that is happening is that you are choosing x successes out of n total trials. Since all are independent, we can just multiply the resulting probabilities. The other trials [n-x trials] that are failures are counted as 1-p.  So, to summarize, out of x chosen successes out of n, we multiply the probability of success x times, and the probability of failure the other n-x times.

So in general we have the formula (n choose x) * (p)^x * (q)^(n-x) where q = 1-p

1.

(5 choose 2) * (.646)^2 * (1-.646)^3  = .1851

2.

(11 choose 9) * (.42)^9 * (1-.42)^2 = .0075