Question 847456
(5 choose 3) * (p)^3 * (1-p)^2 = (6 choose 2) * (p)^2 *(1-p)^4


10*p^3*(1-p)^2 = 15 * p^2 * (1-p)^4

cancel out p's and (1-p)'s

10*p = 15(1-p)^2

10p = 15(1-2p+p^2)

10p = 15 - 30p + 15p^2

15p^2 - 40p +15 = 0

5(3p^2-8p+3) = 0

When applying the quadratic formula we get p = 0.4514, 2.2153.

Since 0<=p<=1, we throw out the 2.21 and we get p = 0.4514.