Question 847398
Let {{{ d }}} = number of dimes
Let {{{ q }}} = number of quarters
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(1) {{{ d + q = 56 }}}
(2) {{{ 10d + 25q = 950 }}} ( in cents )
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Multiply both sides of (1) by {{{ 10 }}}
and subtract (1) from (2)
(2) {{{ 10d + 25q = 950 }}}
(1) {{{ -10d - 10q = -560 }}}
{{{ 15q = 390 }}}
{{{ q = 26 }}}
There are 26 quarters
check:
(1) {{{ d + 26 = 56 }}}
(1) {{{ d = 30 }}}
and
(2) {{{ 10*30 + 25*26 = 950 }}}
(2) {{{ 300 + 650 = 950 }}}
(2) {{{ 950 = 950 }}}
OK