Question 847385
{{{ 16= 6x + x^2 }}}


{{{ 0= 6x + x^2 - 16 }}}


{{{ 6x + x^2 - 16 = 0 }}}


{{{ x^2 + 6x - 16 = 0 }}}


{{{ (x + 8)(x - 2) = 0 }}}


{{{ x + 8 = 0}}} or {{{x - 2 = 0 }}}


{{{ x  = -8}}} or {{{x = 2 }}}


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The two solutions are:


{{{ x  = -8}}} or {{{x = 2 }}}