Question 847292
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Hi,
Finding the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
Completing the Square:  y = ax^2 + bx + c   &#8658; {{{y = a(x -(-b/2a)^2) - a(-b/2a)^2 + c}}}
f(x) = -(1/2)x^2 - 2x     + 5
f(x) = -(1/2)(x^2 +4x)    + 5  
f9x) = (-1/2)(x+2)^2 + 2 + 5 = 
f(x) = (-1/2)(x+2)^2 + 7  
V(-2,7)
{{{drawing(300,300,   -6, 6, -6, 10, grid(1), 
circle(-2, 7,0.2),
circle(0, 5,0.2),
graph( 300, 300, -6, 6, -6, 10,0,-(1/2)x^2 - 2x     + 5 ) )}}}