Question 847327
Solve the following systems algebraically.
{ y = -x + 5
{ y = x + 3
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Add each column to get:
y+y = -x+x + 5+3
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2y = 0 + 8
2y = 8
Divide both sides by 4::
y = 4
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Solve for "x":
y = x + 3
Substitute 4 for y:
4 = x + 3
Subtract 3 from each side to get::
x = 1
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Cheers,
Stan H.
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