Question 748711
prime nos are= 2, 3, 5, 7, 11

now,
sum=2 {(1,1)}
sum=3 {(1,2) (2,1)}
sum=5 {(1,4) (4,1) (2,3) (3,2)}
sum=7 {(1,6) (6,1) (2,5) (5,2) (3,4) (4,3)}
sum=11 {(5,6) (6,5)}
total=15

the no.of possible outcomes is 6*6=36

p(sum=prime no)= 15/36
therefore answer is 5/12