Question 847175
*[tex \large (2x+6)^3 = 8] (by definition of the logarithm).


*[tex \large 2x+6 = 2]. We take the real root, as opposed to *[tex \large 2 \text{cis} \frac{2\pi}{3}] or *[tex \large 2 \text{cis} \frac{4\pi}{3}] since logarithms aren't really well defined for complex bases.


2x = -4, x = -2