Question 847130
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
{{{log(3,(x+1)) - log(3,x) = 2}}}
  {{{log(3,(x+1)/x) = 2 }}}     1st
 {{{3^2 = (x+1)/x}}}      2nd
  9x = x+1
  8x = 1
   x = 1/8
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]  applied 2nd
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]  Applied 1st
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]